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ad-work [718]
3 years ago
13

Help quick! Which one is true?

Mathematics
1 answer:
enot [183]3 years ago
8 0
The first one, i think
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Solve for side in right triangles
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3 years ago
HELP PLEASE!!
cestrela7 [59]

Answer:

Quadrilateral FSHB∼quadrilateral KTWJ.

Step-by-step explanation:

Given two quadrilaterals we have to prove these two similar.

The two quadrilaterals are similar if the corresponding sides of these are proportional then only the quadrilateral are proportional i.e

∴ \frac{FS}{KT}=\frac{SH}{TW}=\frac{HB}{WJ}=\frac{BF}{JK}

If the above condition satisfied then the quadrilateral are similar.

Let us find these ratios

\frac{FS}{KT}=\frac{28}{21}=1.333

\frac{SH}{TW}=\frac{24}{18}=1.333

\frac{HB}{WJ}=\frac{18}{13.5}1.333

\frac{BF}{JK}=\frac{18}{13.5}1.333

All ratios are equal.

Hence, the corresponding sides and angles of these two quadrilaterals are proportional implies that these two are similar i.e quadrilateral FSHB∼quadrilateral KTWJ.




7 0
3 years ago
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