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Firdavs [7]
3 years ago
12

Donna wrapped 45 gifts. Donna wrapped 9 times as many gifts as Hong. Let be the number of gifts that Hong wrapped.

Mathematics
1 answer:
Sloan [31]3 years ago
7 0

Answer:

the answer is 4649461

Step-by-step explanation:

1+1=1

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A company rents out 19 food booths and 26 game booths at the county fair. The fee for a food booth is
rewona [7]

Answer:$4669

Step-by-step explanation:

175x19=3325+5(4)=3345

1300+6(4)=1324

5 0
3 years ago
What expression is equivalent to -0.5x - 4?
Assoli18 [71]

Answer:

2x-32

Step-by-step explanation:

You would distribute the 4.

3 0
2 years ago
Which of the following statements about EF and EG is true?
Ganezh [65]

Answer:

Your answer is B

Step-by-step explanation:

If you count the units you can see that it is 7 units in length.

7 0
3 years ago
A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requi
Vika [28.1K]

Answer:

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 180, \pi = \frac{14}{180} = 0.0778

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 - 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.0387

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 + 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.1169

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

4 0
3 years ago
In checkers, pieces move diagonally. The board shows a move with two consecutive jumps. Write a composition of translations for
dusya [7]

Answer:- The composition of translation is :

Translation: (x,y)→(x-2,y+2)   [as the given piece moved 2 steps to the left and 2 steps upwards]

Translation:(x,y)→(x+2,y+2)   [as the given piece moved 2 steps to the right and 2 steps upwards]

A single translation that moves the piece from its original position to its ending position is  [ignoring the diagonal movement]

Translation:-(x,y)→(x,y-4)[as piece have to go 4 steps downwards]


5 0
3 years ago
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