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3 years ago

Which line segment is not a diameter or radius of circle F?

Mathematics

1 answer:

spin [16.1K]3 years ago

7 0

Short Answer: AB
Argument
Take F to be the center. The line segment that IS a diameter or radius must either go through F (that would make the line a diameter) or to be a radius the segment mus end in F and touch the circumference once. See below.

The diameter must not only go through F, it must touch the circumference in two places. EFB is a diameter. So is AFC

The radius must have 1 endpoint at the center and one endpoint on the circumference. DF is a radius.

So what isn't? Answer: AB isn't. It neither goes through F nor is F one of the end points.

Answer: AB

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Write the equation of a piecewise function with a jump discontinuity at x =3. Then, determine which step of the 3-step test for

seraphim [82]

Answer:

Here's a possible example:

Step-by-step explanation:

$f(x) =\begin{cases} x & \quad x < 3\\x+3 & \quad x \geq 3\\\end{cases}$

Each piece is linear, so the pieces are continuous by themselves.

We need consider only the point at which the pieces meet (x = 3).

$\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) = \lim_{x \longrightarrow 3^{-}} x = 3\\\\\displaystyle \lim_{x \longrightarrow 3^{+}} f(x) = \lim_{x \longrightarrow 3^{+}} x+3 = 6\\\\f(3) = x + 3 = 6\\\\\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) \neq f(3)$

The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.

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3 years ago

HELP DUE IN 15 MINUTES!!!! REFLECTIONS!

Sergeu [11.5K]

D(-1,-1), E(-8,-4), F(-8,-8)

3 0

3 years ago

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What two numbers multiply to get 42 and add to get 25

Nataly_w [17]

12.5×12.5 will give u 42 an if u add it u will get 25

6 0

3 years ago

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago

Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel. How old is kevin now?

puteri [66]

K = Kevin's age
D = Daniel's age

K = 3D

K - 4 = 5(D - 4)

Plug in 3D for the K values in the second equation.

3D - 4 = 5(D - 4) Use the Distributive Property
3D - 4 = 5D - 20 Add 4 to both sides
3D = 5D - 16 Subtract 5D from both sides
-2D = -16 Divide both sides by -2
D = 8
Now, plug that D value into the original equation.

K = 3D Plug in the D value
K = 3(8) Multiply
K = 24

Finally, you can double check your math.

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24.

So, Kevin is 24.

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3 years ago

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