Question

Help pls, math due tonight :(

Answer 1

9514 1404 393

Answer:

• 40 ft
• t = 1 second

Step-by-step explanation:

A graphing calculator answers these questions easily.

The ball achieves a maximum height of 40 ft, 1 second after it is thrown.

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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.

  h(t) = -16(t^2 -2t) +24

  h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square

  h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form

Compare this to the vertex form:

  f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'

We see the vertex of our height equation is ...

  (h, k) = (1, 40)

The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.