Help pls, math due tonight :(
1 answer:
9514 1404 393
Answer:
- 40 ft
- t = 1 second
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
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Answer: <RPS = 161
Step-by-step explanation:
P is the common vertex in all of these angles. From this we know that these have to be adjacent angles (<QPR and <QPS) that equal the whole angle (<RPS)
<QPR+<QPS= <RPS
71+90= 161
(<QPS is a right angle. Right angles are equal to 90 degrees.)
