In decreasing order:
439.612, 439.261, 439.216, 439.126
Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."
Step-by-step explanation: I think this is the problem ur on
Answer:
12
Step-by-step explanation:
Let's put the equations in standard form. For the first equation, we have:
−11y=6(z+1)-13y
2y−6z=6
y−3z=3
The second equation is:
4y−24=c(z−1)
4y−cz=24−c
If we multiply the first equation by 4, we get:
4y-12z=12
Comparing the two equations, we see that if c=12, both equations will be the same and there will be infinitely many solutions.
The correct value of c is 12.
