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valentina_108 [34]
3 years ago
10

What is the equation for a line parallel to y=-4x-9 that passes through the point 0,8

Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0
Parallel = same slope
Y = -4x + b
(0,8) y intercept; plug in
Solution: y = -4x + 8
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How do you put f(8)=-1,f(6)=0 into point slop form?​
Mademuasel [1]

Answer:

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute [SF]:                    m=\frac{0+1}{6-8}
  2. Add/Subtract:                      m=\frac{1}{-2}
  3. Simplify:                               m=\frac{-1}{2}

<u>Step 3: Write Function</u>

<em>Substitute into general form.</em>

  • Point 1: y + 1 = -1/2(x - 8)
  • Point 2: y = -1/2(x - 6)
4 0
3 years ago
I need help on this equation 6s-10=s
dusya [7]
The equation:                           6s - 10  =  s

Add  10  to each side:             6s         =  s  +  10

Subtract 's' from each side:    5s         =          10

Divide each side by  5 :            s          =            2
3 0
3 years ago
Cylinder capacity 4.25 L, cylinder diameter of 13 what is the height of the cylinder?
Musya8 [376]

Answer:

Step-by-step explanation:

Capacity of cylinder =4.25L

So volume of the cylinder=4250

πr^2h=4250

3.14×6.5×6.5×h=4250

132.665h=4250

h=4250/132.665

h=32.035

6 0
3 years ago
The distance between the points (-3,-1) and (-4,0) is the square root of ___?
Galina-37 [17]
\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -3}}\quad ,&{{ -1}})\quad &#10;%  (c,d)&#10;&({{ -4}}\quad ,&{{0}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
6 0
3 years ago
PLEASE HELP QUICKLY!!
Effectus [21]

Answer:

X int: (-3,0)

y int: (0,-6)

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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