Convert the decimal 3.88888… to a fraction.

Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS

olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....$

where, n = number of trials (samples) taken = 36 couples

r = number of success

p = probability of success which in our question is probability

of a girl, i.e.; p = 0.5

Let X = Numbers of girls in groups of 36 births

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

Mean, E(X) = $n \times p$ = $36 \times 0.5$ = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

Standard deviation, S.D.(X) = $\sqrt{n\times p\times (1-p)}$

= $\sqrt{36\times 0.5\times (1-0.5)}$

= 3

3 0

3 years ago

Which of the following statements correctlydescribes the points

gregori [183]

The first statement is correct

To calculate the distance we have to substrate the values of the Y axis only since X values are constant so the distance IS 4 - - 7=4+7=11

4 0

3 years ago

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if you repeat the perpendicular line segment construction twice using paper folding, you can construct:

ehidna [41]

Answer:

The correct answer is option C.

The mid point of the line segment.

Step-by-step explanation:

the perpendicular line segment construction twice using paper folding

we have to find the mid point of the given line segment.

We get the midpoint easily when fold the paper correctly

Therefore the correct answer is option C.

The mid point of the line segment.

6 0

3 years ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. Chris is playing a

alisha [4.7K]

Let's call the aces $h, d, c, s$ for hearts, diamonds, clubs and spades. So, $h, d$ are red and [ted] c, s[/tex] are black.

Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple

$(x,y)\, x, y \in \{h,d,c,s\}$

There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:

If we want a player to draw two card of the same colour, the following couples are good:

$(h,h),\ (h,d),\ (d,h),\ (d,d),\ (c,c),\ (c,s),\ (s,c),\ (s,s)$

so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.

Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:

$(h,c),\ (h,s),\ (d,c),\ (d,s)$

which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.

4 0

4 years ago

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I need help on 26, 27, 28, and 29

gogolik [260]

Answer:

29- x=59

Step-by-step explanation:

4 0

3 years ago