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zzz [600]
3 years ago
10

Convert the decimal 3.88888… to a fraction.

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

.8 repeating would be 8/9 so D

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a jewler buys a ring from an artisan for 85$. He sells the ring at his store at 135% increase in price. What is the retail price
ELEN [110]
<span>A jeweler buys a ring from an artisan for 85$. He sells the ring at his store at 135% increase in price. What is the retail price? PLEASE SHOW UR WORK!!!

1.35(</span><em>135%</em><span>) x  85( <em>the price it was bought for</em>)

= $114.75


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4 0
3 years ago
Please help picture shown
SashulF [63]
\dfrac{x}{x-5} ~ \cdot~ \dfrac{2x}{x+4} =\dfrac{x~ \cdot~ 2x}{(x-5)(x+4)}= \dfrac{2x^2}{x^2 -x -20}

The answer is D.

Hope it helps!
5 0
3 years ago
Convert logx y = 1/2 to exponential form.
Lena [83]

Answer:

Exponential form: y = x^½

Step-by-step explanation:

Given

log_xy= \frac{1}{2}

Required:

The exponential form

To convert to an exponential function, we have to take exponents of both sides using the base of the logarithm function.

This gives us

x^{log_xy}= x^\frac{1}{2}

Since the base of the exponential function and the logarithm is the same (x), they'll cancel out one another

This leaves us with

y= x^\frac{1}{2}

Hence, the exponential form of the expression

log_xy= \frac{1}{2} is y= x^\frac{1}{2}

8 0
3 years ago
I need help please.
Maslowich

Answer:

7-5m/m

Step-by-step explanation:

3 0
3 years ago
In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the
Volgvan

Answer:

P =4.83\%

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

nCr=\frac{n!}{r!(n-r)!}

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

4C1 = 4

The number of ways to choose a 10-point letter is:

16C1 = 16

Therefore, the number of ways to choose an Ace and a 10-point card is:

4C1 * 16C1 = 4 * 16 = 64

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

52C2 =\frac{52!}{2!(52-2)!}

52C2 = 1326

Therefore, the probability of obtaining an "blackjack" is:

P = \frac{4C1 * 16C1}{52C2}

P = \frac{64}{1326}

P = \frac{32}{663}

P =0.0483

P =4.83\%

4 0
3 years ago
Read 2 more answers
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