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3 years ago

What is the value of y, given x=6 and the equation y= 0.5x + 7

Mathematics

2 answers:

barxatty [35]3 years ago

5 0

Answer:

Step-by-step explanation:

y=(0.5)6+7

y=3+7

y=10

vodka [1.7K]3 years ago

4 0

Answer:

the value is 10

Step-by-step explanation:

y = 0.5(6) + 7

y = 3 + 7

y = 10

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Which expression is equivalent to ? Assume.

nikdorinn [45]

Answer:

2. $-2x^{8}y^{18}$

Step-by-step explanation:

We have been given an expression $\frac{10x^{6}y^{12}}{-5x^{-2}y^{-6}}$ and we are asked to find equivalent expression to our given expression.

Using fraction rule $\frac{a}{-b} =-\frac{a}{b}$ we can write our expression as: $-\frac{10x^{6}y^{12}}{5x^{-2}y^{-6}}$ .

Upon dividing 10 by 5 we will get,

$-\frac{2x^{6}y^{12}}{x^{-2}y^{-6}}$

Upon using exponent property for quotient $(\frac{a^{m}}{a^{n}} =a^{(m-n)})$ we will get,

$-\frac{2x^{6}y^{12}}{x^{-2}y^{-6}}=-2x^{(6--2)}y^{(12--6)}$

$-2x^{(6+2)}y^{(12+6)}$

$-2x^{8}y^{18}$

Therefore, our expression simplifies as $-2x^{8}y^{18}$ and 2nd option is the correct choice.

6 0

3 years ago

Read 2 more answers

Pls give an explanation w your answer

Shalnov [3]

$a^{\frac{1}{n}}=\sqrt[n]{a}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}$
therefore
$64^\frac{1}{4}=\left(2^6\right)^\frac{1}{4}=2^{6\cdot\frac{1}{4}}\\\\=2^\frac{6}{4}=2^{1\frac{2}{4}}=2^{1+\frac{2}{4}}=2\cdot2^\frac{2}{4}\\\\=2\sqrt[4]{2^2}=2\sqrt[4]4$
Other method:
$64^\frac{1}{4}=\sqrt[4]{64}=\sqrt[4]{16\cdot4}=\sqrt[4]{16}\cdot\sqrt[4]4=2\sqrt[4]4$

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4 0

2 years ago

Read 2 more answers

Help! please show some sort of proof! thanks xo

Vadim26 [7]

Answer:

I think it is B I am sorry if wrong

5 0

3 years ago

What is the solution to the equation m/m+4 +4/4-m = m^2/ m^2- 16 ?

nignag [31]

The answer is 2 i think