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Lina20 [59]
3 years ago
11

What is the length of BC

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0
I'm pretty sure your answer is 17
Nana76 [90]3 years ago
6 0
Very sorry it doesn't let me see the attachment.
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LuANN is playing a math game. She chooses 3 cards. The value of her cards is hownn below
Rufina [12.5K]
I believe it is -14 :)
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2 years ago
Please use the following image in order to answer the question correctly:
andriy [413]

Answer:

134 degrees.

Step-by-step explanation:

This is a simple one.

The arc RS subtends an angle of 67 degrees on the circumference,

So the measure of the arc RS is 2 * 67 = 134 degrees.

3 0
3 years ago
I’m confused please help
Maru [420]
<h2>Hello!</h2>

The answer is:

Sin(A)=0.93

<h2>Why?</h2>

To solve the problem, remember to set your calculator in "degree mode"

So, we are given that the angle A is equal to 68°

So, we have that:

Sin(A)=Sin(68\°)=0.93

Hence, we have that:

Sin(A)=0.93

Have a nice day!

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3 years ago
What is the area of Figure ABCD?
Veseljchak [2.6K]
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Read 2 more answers
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
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