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3 years ago

I NEED MAJOR HELP What's the volume of the cone?

Mathematics

2 answers:

Mashutka [201]3 years ago

5 0

Answer:

The volume of a cone is 1/3bh

Step-by-step explanation:

madam [21]3 years ago

4 0

263.89 m^3 or 84(pi) m^3

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Y is inversely proportional to x when y=9, x=24

Lisa [10]

Answer:

216

Step-by-step explanation:

y=k÷x

k=xy

k=9×24

k=216

7 0

3 years ago

Maria puts $2,500.00 in her money market account earning 8% interest annually. How much interest and how much money would she ha

Gnom [1K]

The correct answer: total interest = $1,784.56 and she would have $4,284.56 after 7 years

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3 years ago

Please help! It will be appreciated!

AysviL [449]

It’s d, looks like you got it already! With ratios, just pay attention to not only the numbers but order of the words as well, so you can be sure the ratio follows the problem.

8 0

3 years ago

Read 2 more answers

Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

3 years ago

What is the slope of the line perpendicular to a line that contains the points (-5,4) and (-2,4)

steposvetlana [31]

Answer:

the slope of the line is: 0

Step-by-step explanation:

4-4=0

-2-5= 3

7 0

3 years ago