Exponential growth of the form:
F=Ar^t
F=100(1.22)^t
F(5)=100(1.22)^5
F(5)=270.27
F(5)=270 to the nearest frog...
....
1.22=r^12
r=1.22^(1/12)
F=100(1.22^(1/12)^t)
F=100(1.22^(t/12)) now it will produce monthly populations...
Say we did the same as before but instead of 5 years you have 60 months...
F(60)=100(1.22^(60/12))
F(60)=270 to the nearest frog... :P
Answer:
0.004462m²
612000m²
0.0482m²
Step-by-step explanation:
Using the conversion
1mm² = 10^-6m²
4462mm² = x
Cross multiply
1 * x = 4462 * 10^-6
x = 4462 * 10^-6
x = 4.462 * 10^3 * 10^-6
x = 4.462*10^{3-6}
x = 4.462*10^-3
x = 0.004462m²
Hence 4462 mm² in m² is 0.004462m²
0.612 km² in m²
1km² = 10^6m²
0.612km² = y
Cross multiply
1 * y = 0.612 * 10^6
y = 0.612*1,000,000
y = 612000m²
Hence 0.612 km² in m² is 612000m²
482 cm² in m²
1cm² = 0.0001m²
482 cm² = z
z = 482 * 0.0001
z = 0.0482m²
Hence 482 cm² in m² is 0.0482m²
Answer:
(5h-4t)(5h+4t)
Step-by-step explanation:
25h² - 16t²
adding and subtracting 20ht from it (√25 and √16 = 5x4 = 20):
25h² + 20ht - 20ht -16t²
factor:
(5h-4t)(5h+4t)
The exact answer is 2,165.846153846154
Hope this helpssss :)
