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Dominik [7]
3 years ago
11

What is 126 divided by 14?

Mathematics
1 answer:
lana66690 [7]3 years ago
7 0
\frac { 126 }{ 14 } \\ \\ =\frac { 63\cdot 2 }{ 7\cdot 2 } \\ \\ =\frac { 63 }{ 7 } \\ \\ =9
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What is 11/12 as a decimal
S_A_V [24]

it would be 0.9167 as a decimal. I hope this helps :)

7 0
3 years ago
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Does anyone know why I only got 2/3 marks, and can you explain how to get 3 marks please. Please answer.
Brums [2.3K]

Answer:

294cm²

Step-by-step explanation:

You didn’t convert from meters to centimeters.

It was 2.94m².

That equals 294cm².

5 0
2 years ago
A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long
Pie

Answer:

Surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

S = \frac{1}{2}pl+B                                       ...... (1)

Here, p represents the perimeter of the base , l the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid(l) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = 3 \times (side)

                                                          = 3 \times 20 = 60 inches

Area of equilateral triangle(B) = \frac{\sqrt{3} }{4} \times (side)^{2}

                                                 =\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}  square inches.

Substitute the above values in equation (1) as shown below:

S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}

S= 390+100\sqrt{3} square inches

Hence, the surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches.

6 0
3 years ago
A2+(b−c); a=−8, b=17, c=21
JulsSmile [24]
You’re answer should be 60
8 0
3 years ago
Point B has coordinates ​(3​,2​). The​ x-coordinate of point A is −6. The distance between point A and point B is 15 units. What
xxTIMURxx [149]

Answer:

Distance between two points= √(x2-x1)²+(y2-y1)²

D= 15units

Let "k" be the y-coordinate of A

A(-6,k)

B(3,2)

15= √(3--6)²+(2-k)²

Taking square of both sides to eliminate the square root.

15²=(9)²+(2-k)²

225=81+4-4k+k²

k²-4k - 140=0

Using Quadratic Formula to evaluate

k= 14 or k=-10

The Possible coordinates of A are

(-6,14) or (-6,-10)

4 0
2 years ago
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