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2 years ago

what is the equation of the line that is perpendicular to the given line and has an x-intercept of 6?

Mathematics

1 answer:

yaroslaw [1]2 years ago

6 0

Answer:

y = 4/3x - 6

Step-by-step explanation:

The slope of the 1st line is -3/4

So for the perpendicular line it has to be the exact opposite.

That looks like this ---> 4/3x

And the y-intercept is -6 because if you make a straight line where the x intercept is it matches.

The equation would look like this

y = 4/3x - 6

Hope this helps! Have a blessed day!

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3 years ago

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OM , ON and OP are the angle bisectors of ∠AOB, ∠BOC, and ∠COD respectively. ∠AOD and ∠BOE are straight angles.

Orlov [11]

Find m∠BOC, if m∠MOP = 110°.

Answer:

m∠BOC= 40 degrees

Step-by-step explanation:

A diagram has been drawn and attached below.

OM bisects AOB into angles x and x respectively
ON bisects ∠BOC into angles y and y respectively
OP bisects ∠COD into angles z and z respectively.

Since ∠AOD is a straight line

x+x+y+y+z+z=180 degrees

$2x+2y+2z=180^\circ$

We are given that:

m∠MOP = 110°.

From the diagram

∠MOP=x+2y+z

Therefore:

x+2y+z=110°.

Solving simultaneously by subtraction

$2x+2y+2z=180^\circ$

x+2y+z=110°.

We obtain:

x+z=70°

Since we are required to find ∠BOC

∠BOC=2y

Therefore from x+2y+z=110° (since x+z=70°)

70+2y=110

2y=110-70

2y=40

Therefore:

m∠BOC= 40 degrees

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2 years ago

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2 years ago

what is the equation of the line that is perpendicular to the given line and has an x-intercept of 6?​

what is the equation of the line that is perpendicular to the given line and has an x-intercept of 6?