Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG and GH HE (2) EG FH (3) EG FH (4) EF HG
1 answer:
Answer:
EF = HG and EF || HG
Step-by-step explanation:
A quadrilateral is a polygon shape with four sides and four angles.
A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:
- Opposite sides are equal and parallel.
- Opposite angles are equal to each other.
- Consecutive angles are supplementary
- The diagonals of a parallelogram bisect each other.
If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG
You might be interested in
Answer:
90π units²
Step-by-step explanation:
(refer to attached)
Total Surface are off a right cylinder = area of its ends + area of curved surface
Given radius, r = 3 units and height, h = 12 units
Area of 2 ends,
= Area of 2 circles
= 2 x πr²
= 2π (3²)
= 2π (9)
=18π units²
Area of curved surface,
= 2πrh
= 2π(3)(12)
= 72π units²
Hence,
Surface area = 18π + 72π = 90π units²
