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3 years ago

A cheetah ran 330 feet in 3.92 seconds. What is the cheetah’s average speed in miles per hour

Mathematics

1 answer:

Pavel [41]3 years ago

8 0

Answer:

So its 70.05 miles per hour Hope this helped :)

Step-by-step explanation:

Cheetah ran 300 feet in 2.92 seconds.

Average speed in miles per hour.

Converting 300 feet to mile.

5280 feet = 1 mile

1 feet = (1/5280) mile

300 feet = (1/5280) * 300 = (300/5280) = (30/528) = (10/176) mile.

2.92 seconds to hour.

3600 seconds = 1 hour

1 second = (1/3600) hour

2.92 seconds = 2.92 * (1/3600) = (2.92/3600) hour.

Speed of Cheetah in miles per hour = (10/176) mile / (2.92/3600) hour

= 70.05 miles/hour

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Answer:

let one even number be N

and another even number be N(N+2)

N(N+2)=360

n^2+2n-360=0

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but -20 not accepted

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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47.6001
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4 years ago

Average rate of change from x= 1 and x=2

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Answer:

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Step-by-step explanation:

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3 years ago

According to industry sources, online banking is expected to take off in the near future. The projected number of households (in

Airida [17]

Answer:

(a) The least-square regression line is: $y=4.662+2.709x$ .

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

(a)

The formula to compute intercept and slope is:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \end{aligned}$

The values of ∑X, ∑Y, ∑XY and ∑X² are computed in the table below.

Compute the value of intercept and slope as follows:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}$

The least-square regression line is:

$y=4.662+2.709x$

(b)

For the year 2007 the value of x is 10.

Compute the value of y for x = 10 as follows:

$y=4.662+2.709x$

$=4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8$

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

5 0

3 years ago