The value of the radius of T is 28 units
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How to determine the value of the radius of T</h3>
From the question, we understand that:
Segment AB is tangent to T at B
This means that
<ABT = 90
So, we have a right triangle
Let the radius of the triangle be r
By the Pythagoras theorem, we have
AT^2 = AB^2 + VT^2
This gives
(25 + r)^2 = 45^2 + r^2
Open the bracket
625 + 50r + r^2 = 2025 + r^2
Subtract r^2 from both sides of the equation
625 + 50r = 2025
Subtract 625 from both sides of the equation
50r = 1400
Divide both sides by 50
r = 28
Hence, the value of the radius of T is 28 units
Read more about tangent at:
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Answer:
i think c
Step-by-step explanation:
sorry if im wrong
Answer: 12.57 sq mm
Step-by-step explanation:
Area of a circle = pi r^2
Take a look at the horiz. line. It has arrows at both ends. That means that x goes on forever in both directions. Thus, the domain of this function is (-inf, +inf).
Answer:
Step-by-step explanation:
1.first 330,000 divided by 100 wich Is 3300 then multiply that by 4 wich is 13,200
2. then 330,000 divided by 1000 wich is 330 multiply that by 5 wich is 1,650
3. Add 1,650 + 13,200 + 330,000 wich is 344,850.00 so a
