Answer:
Domain: (-3,-2,0,1,2,3)
Range: (9,4,1,0,1,4,9)
Step-by-step explanation:
Answer:
2x +2x=90
ZRQ
Step-by-step explanation:
FOR THE FIRST ONE, SUM OF ANGLES IN A TRIANGLE IS 180 AND SINCE WE KNOW ONE ANGLE IS 90° THE REST WOULD ADD UPTO 90°
THE SECOND ONE, JUST FOLLOW THE SEQUENCE OF THE MARKED LINES
for XYZ they went from the unlabeled line to the double marked line to the single marked line. similarly go for ZRQ
Answer:
R (t) = 60 - 60 cos (6t)
Step-by-step explanation:
Given that:
R(t) = acos (bt) + d
at t= 0
R(0) = 0
0 = acos (0) + d
a + d = 0 ----- (1)
After 
seconds it reaches a height of 60 cm from the ground.
i.e
Recall from the question that:
At t = 0, R(0) = 0 which is the minimum
as such it is only when a is negative can acos (bt ) + d can get to minimum at t= 0
Similarly; 60 × 2 = maximum
R'(t) = -ab sin (bt) =0
bt = k π
here;
k is the integer
making t the subject of the formula, we have:
replacing the derived equation of k into R(t) = acos (bt) + d
Since we known a < 0 (negative)
then d-a will be maximum
d-a = 60 × 2
d-a = 120 ----- (3)
Relating to equation (1) and (3)
a = -60 and d = 60
∴ R(t) = 60 - 60 cos (bt)
Similarly;
For 
where ;
Then b = 6
∴
R (t) = 60 - 60 cos (6t)
Here you go hope this helps!
Step-by-step explanation:
14)
Simplifying
3m + 5 = 4m -10
Reorder the terms:
5 + 3m = 4m -10
Reorder the terms:
5 + 3m = -10 + 4m
Solving
5 + 3m = -10 + 4m
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '-4m' to each side of the equation.
5 + 3m + -4m = -10 + 4m + -4m
Combine like terms: 3m + -4m = -1m
5 + -1m = -10 + 4m + -4m
Combine like terms: 4m + -4m = 0
5 + -1m = -10 + 0
5 + -1m = -10
Add '-5' to each side of the equation.
5 + -5 + -1m = -10 + -5
Combine like terms: 5 + -5 = 0
0 + -1m = -10 + -5
-1m = -10 + -5
Combine like terms: -10 + -5 = -15
-1m = -15
Divide each side by '-1'.
m = 15
Simplifying
m = 15
(thank to <em>geteasysolution</em> . com
15)
xy+yz=xz
a+a+8=50
2a=42
a=21
a+8=29
