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2 years ago

6

PLEASE ME I HAVE HELP

1 answer:

DENIUS [597]2 years ago

8 0

Answer:

what?

Step-by-step explanation:

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4 bottles of water cost 10 dollars at a music festival.

TiliK225 [7]

Answer:

7 dollars and 50 cents, price per bottle is 2 dollars (you can get this answer by dividing 10/4) and 50 cents multiply that by 3 and you get the answer, 7 dollars and 50 cents.

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

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2 years ago

The general form of an exponential function is y = abx. Use the regression calculator to find the values of a and b for the wate

Arisa [49]

Answer:

a=3.915 and b=1.106

Step-by-step explanation:

This is the answer on edju

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2 years ago

Read 2 more answers

The perimeter of a rectangle is 46 m if the with were doubled and on length were increased by 5 their perimeter would be 66 what

Kamila [148]

Answer:

18 and 5

Step-by-step explanation:

if 'x' - is the length and 'y' - the width of the rectangle, then

2(x+y)=46 - perimeter of the original rectangle and 2(2x+(y+5))=66 - the perimeter of the new rectangle.

$\left \{ {{x+y=23} \atop {2x+y=28}} \right. \=> \ \left \{ {{x=5} \atop {y=18}} \right.$

Finally, the length is x=5 and the width is y=18.

8 0

2 years ago

submarine A is currently at a depth of 432 feet below sea level Submarine B is onky at a depth of 3/4 as much as Submarine A. Wh

alexandr402 [8]

Well you could multiply 432 by 0.75, or you can divide it by 4 and then multiply it by 3. Either way your answer is 324.

8 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago