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Vesnalui [34]
3 years ago
7

In his first 64 games, Sasha hit 48 home runs. If he continues at that rate, how many home runs will Sasha hit in his next 272 g

ames?
A. 204
B.56
C.100
D.216
Mathematics
1 answer:
telo118 [61]3 years ago
8 0

Answer:

A

Step-by-step explanation:

272/64 = 4.25

4.25*48 = 204

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Naddika [18.5K]

Answer:

55 performances

Step-by-step explanation:

The first equation will be the total cost. The total cost has $88,000 already and then $5,900 is added with each performance. So the equation would be 88,000+5,900x because x will represent the number of performances.

y = 88,000 + 5,900x

The next equation will be how much the performances earn. If they earn $7,500 with each performance then the equation will be 7,500x, with x representing the number of performances

y = 7,500x

Now set the equations equal to each other and solve for x

7,500x = 88,000 + 5,900x

1,600x = 88,000

x = 55

They need to have 55 performances for the cost and the revenue to break even.

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3 years ago
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trasher [3.6K]

7 x 3 = 21 so it is 21 ft cm your welcome

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2 years ago
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ivann1987 [24]

9514 1404 393

Answer:

  • large: 55 lb
  • small: 30 lb

Step-by-step explanation:

Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...

  x + y = 85 . . . . . combined weight of a large and small box

  70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes

We can subtract 50 times the first equation from the second to find the weight of a large box.

  (70x +50y) -50(x +y) = (5350) -50(85)

  20x = 1100 . . . . simplify

  x = 55 . . . . . . . divide by 20

Using this in the first equation, we can find the weight of a small box.

  55 +y = 85

  y = 30 . . . . . . . subtract 55

A large box weighs 55 pounds; a small box weighs 30 pounds.

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Answer:

f(n)=\frac{1}{3}n

Step-by-step explanation:

To convert from feet to yards, divide by the value 3.

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2 years ago
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ivanzaharov [21]

Step-by-step explanation:

The median is the middle number is an ordered set of data. In a frequency table, the observations are already arranged in an ascending order. We can obtain the median by looking for the value in the middle position. If there is an odd number of observations, the median is the middle number

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