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lyudmila [28]
3 years ago
11

Adding/Subtracting rational expressions

Mathematics
1 answer:
Leona [35]3 years ago
5 0
7]
 6/(x-1)-5x/4
subtracting the above we put the fraction under the same denominator:
 6/(x-1)-5x/4
multiplying the denominators we get:
4(x-1)
thus subtracting we get:
6/(x-1)-5x/4
=(4*6-5x(x-1))/[4(x-1)]
=[24-5x^2+5x]/(4x-4)
Answer:
(-5x^2+5x+24)/(4x-4)


9]
3/(x+7)+4/(x-8)
the common denominator is:
(x+7)*(x-8)=(x+7)(x-8)
thus adding the fractions we put them under the same denominator as follows:
[3(x-8)+4(x+7)]/[(x+7)(x-8)]
=[3x-24+4x+28]/[(x+7)(x-8)]
=(7x+4)/[(x+7)(x-8)]

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Which inequality can Josh use to determine x, the minimum number of visits he needs to earn his first free movie ticket?
MissTica

Answer:

3.5x + 15 ≥ 55

Step-by-step explanation:

I think the question below contains the missing information.

<em>Josh has a rewards card for a movie theater. - He receives 15 points for becoming a rewards card holder. - He earns 3.5 points for each visit to the movie theatre. - He needs at least 55 points to earn a free movie ticket. Which inequality can Josh use to determine x, the minimum number of visits he needs to earn his firs free movie ticket? </em>

My answer:

  • Becoming a member = 15 points
  • Visiting the moving theater = 3.5 points
  • Total points needed for a free movie ticket = 55

Let x is the number of times he visits = 3.5x

Total points = Points received on becoming a member + Points received on x visits

So,

Total Points = 15 + 3.5x

We know the total points must be at least 55 for a free movie ticket.  This can be expressed as:

3.5x + 15 ≥ 55

6 0
3 years ago
the Ratio of Chaperones to student on a field trip is 2:7 . There are 14 Chaperones on the field trip . In all , how many chaper
ozzi

Answer:

63

Step-by-step explanation:

If the 2 in the ratio translates to 14, 14/2=7. So the scale factor is 7. Now we multiply the 7*(Scale Factor)(7)= 49. In the end we add 14+49 to get 63.

5 0
4 years ago
Read 2 more answers
Write a decimal that represents the value of one 1.00 bill and 5 quarters
oee [108]
$1.00

5 quarters=$1.25
5 0
3 years ago
How many whole numders have the sum of 40
cluponka [151]

Answer:

We start with 0 + 40.

1. 0 + 40

2. 1 + 39

3. 2 + 38

4. 3 + 37

.....

keep going....

.....

19. 18 + 22

20. 19 + 21

21. 20 + 20

There are 21 pairs of whole numbers that have a sum of 40.

Step-by-step explanation:

hope this helps :)

6 0
3 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
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