d) You have a <u>difference of squares</u>:
49y² - 9 = (7y)² - 3²
Recall the identity,
a² - b² = (a - b) (a + b)
So,
49y² - 9 = (7y - 3) (7y + 3)
e) Pull out the common factor 3 from each term:
3x² - 3x - 90 = 3 (x² - x - 30)
Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so
3x² - 3x - 90 = 3 (x + 5) (x - 6)
f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so
x² - 13x + 42 = (x - 7) (x - 6)
SOLUTION:
Alternate angles on paralell lines.
This means:
2x + 10° = 62°
2x = 62 - 10
2x = 52
x = 52 / 2
x = 26
Sorry, I tried to answer this but I only got this far. I'm not exactly sure about the ? < x < ? as my answer didn't give an answer with > or <. Unless there are different numbers which you can put for your answer based on what ( x ) is equal to, I'm not sure what the answer is & I doubt that they would allow for multiple answers.
The answer to the question is all real numbers except 2 and 4.
Answer:
760 attendees
Step-by-step explanation:
40% of the attendees is 304. That means you can add 304 to 304 (304 x 2) to get 608. To get the last 20%, divide 304 by 2, because 40(%) divided by 2 is 20(%). The answer to that is 152. Now, add it all up. 608 + 152 = 760.
In conclusion, there were 760 attendees at the carnival.