Answer with Step-by-step explanation:
We are given that displacement of wave
Where y in cm and t in sec.
a.Compare it with
Amplitude of wave=A
We get A=1.5
Amplitude=A=1.5 cm
b.k=0.68
Using 
Wavelength of the wave=9.2 cm
c.Period=
The period of the wave=0.17 s
Speed of the wave=
Speed of the wave=54.1 cm/s
You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.
The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.
For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is
(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²
Answer:
12.68 de
Step-by-step explanation:
First, we determine the slope of the line given, y = 2x + 5
The equation is in slope-intercept where in the slope of the line is the numerical coefficient of x. The slope is therefore 2.
The equation of the new line becomes,
y - 6 = 2(x - 4)
Simplifying, y = 2x - 2
Answer:
C
Step-by-step explanation:
Edge 2021
