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Westkost [7]
3 years ago
13

I learned this 4 months ago and now I forgot how to do it.....

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

b ty

Step-by-step explanation:

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In chemistry class, Bob recorded the volume of a liquid as 13.2 mL. The actual volume was 13.7 mL. Use the formula to find perce
frez [133]
Experimental value=13.2mL
actual volume=13.7mL

|13.2-13.7|=|-0.5|=0.5
0.5/13.7 *100%=3.7%
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3 years ago
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Find x<br><br> -x = 7x - 56
solmaris [256]

Answer:

the answer is 7

Step-by-step explanation:

Add the same term to both sides of the equation

-x=7x-56

−x=7x−56

−x−7x=7x−56−7x

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Jessie typed the first 300 words of her essay in 12 minutes. She then got tired and typed the remaining 300 words of her essay i
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The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
PLEASE HELP ASAP this is for Distribution Area Model (Algebraic) :(
gayaneshka [121]
I believe that answer is 54
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3 years ago
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