Ask question

Ask question

All categories

liberstina [14]

3 years ago

15

The area of the base of a prism is 24 mm2. The perimeter of the base is 22 mm. The height of the prism is 5 mm.

2 answers:

DIA [1.3K]3 years ago

3 0

The surface area = The area of the two bases + the area of the lateral surface

The area of 1 base = 24 mm², so the area of two is 48 mm².

The area of the lateral surface = the perimeter of the base × the height.
The perimeter = 22 mm. The height = 5 mm.
Thus the lateral surface area is 110 mm².

The total surface area is 110 + 48 = 158 mm².

Alexus [3.1K]3 years ago

3 0

<span>The surface area = The area of the two bases + the area of the lateral surface

The area of 1 base = 24 mm², so the area of two is 48 mm².

The area of the lateral surface = the perimeter of the base × the height.
The perimeter = 22 mm. The height = 5 mm.
Thus the lateral surface area is 110 mm².

The final answer is 158mm to the power of 2</span>

You might be interested in

Help me please I'm having trouble with this problem

sweet [91]

The answer is (4,6) (4,3) (5,4)

7 0

3 years ago

100÷10-9[46-5(6)] power 3

Lapatulllka [165]

Answer:

-36864

Step-by-step explanation:

100 ÷ 10=10

(a)=a

(46-5x6) power 3=16

9x16 power 3 =36864

10-36864

=-36864

5 0

3 years ago

7m or 7.7 m which is more precise?

Karolina [17]

7.7 meters is more precise.

7 0

4 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

Which of the following would appear in the Credits column of a bank

KATRIN_1 [288]

The correct answer is A i say this because it makes the most sense. have a wonderful day. i hope this helps

5 0

4 years ago

Read 2 more answers