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3 years ago

What is the perimeter. Show your work.

Mathematics

1 answer:

Sphinxa [80]3 years ago

6 0

The perimeter is 14 because the perimeter formula is-> 2L + 2W. So, 2(3) + 2(4) =14

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A customer goes to a bank and gets change for a $100 bill. The change is to be in $1, $5, and $10 bills. There were four times a

alexira [117]

Answer:

Step-by-step explanation:

x = number of $1 bills

y = number of $5 bills

z = number of $10 bills

We know that:

x + y + z = 25 (total amount of bills)

x + 5y + 10z = 100 (total amount of money)

y = 4z (Given)

Substitute the third equation into the first one.

x + 4z + z = 25

x = 25 - 5z

Put this into the second equation.

(25 - 5z) + 5 (4z) + 10z = 100

Simplify and solve.

25 - 5z + 20z + 10z = 100

25z + 25 = 100

25z = 75

z = 3

Substitute this into y = 4z

y = 4 * 3

y = 12

So, there are 12 $5 bills.

5 0

2 years ago

Read 2 more answers

-3|r+4|=-21 need help for a friend

KonstantinChe [14]

Ans given below

-3r-12=-21
-3r=-21+12
-3r=-9
r=-9\-3
r=3

4 0

3 years ago

In a large single-elimination basketball tournament, the first round of play begins with 64 teams. In each successive round, the

yan [13]

Answer:

f(n)=f(n-1)÷2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

(x-yi)(3+5i) is the conjugate of 6+24i

Nataly_w [17]

Answer:

x=-3

y=3

(-3-3i)(3+5i)

Step-by-step explanation:

$(x-yi)(3+5i)\\=3x+5xi-3yi+5y\\=(3x+5y)+(5x-3y)i\\$

and we have that must equal

6-24i

3x+5y=6

5x-3y=-24 and if we work it we found out that the solutions are

x=-3 and

y=3

5 0

3 years ago

?? So lost with this

labwork [276]

Answer:

$A)\ 1,\ -1,\ -3\\\\B)\ d=-2\\\\C)\ \left\{\begin{array}{ccc}a_1=11\\a_n=a_{n-1}-2\end{array}\right\\\\D)\ f(n)=-2n+13$

Step-by-step explanation:

It's an arithmetic sequence.

9 = 11 - 2

7 = 9 - 2

5 = 7 - 2

3 = 5 - 2

A) next three terms: 3 - 2 = 1, 1 - 2 = -1, -1 - 2 = -3

B) Common difference = -2

C) Recursive Function:

$\left\{\begin{array}{ccc}a_1=11\\a_n=a_{n-1}-2\end{array}\right$

D) Explicit Function:

$f(n)=a_1+(n-1)d$

a₁ - first term

d - common difference

Substitute a₁ = 11 and d = -2:

$f(n)=11+(n-1)(-2)=11-2n+2=-2n+13$

4 0

3 years ago