![(8a^{-3})^\frac{2}{3}=(8 \cdot \frac{1}{a^3})^\frac{2}{3}=(\frac{8}{a^3})^\frac{2}{3}=\sqrt[3]{(\frac{8}{a^3})^2}=\sqrt[3]{\frac{64}{a^6}}=\frac{\sqrt[3]{64}}{\sqrt[3]{a^6}}=\frac{4}{a^2}](https://tex.z-dn.net/?f=%288a%5E%7B-3%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%288%20%5Ccdot%20%5Cfrac%7B1%7D%7Ba%5E3%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%28%5Cfrac%7B8%7D%7Ba%5E3%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B8%7D%7Ba%5E3%7D%29%5E2%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7Ba%5E6%7D%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B%5Csqrt%5B3%5D%7Ba%5E6%7D%7D%3D%5Cfrac%7B4%7D%7Ba%5E2%7D)
It doesn't equal any of the answers A, B, C.
The answer is D.
Answer:
<h2>
r(x+2) = 2x² + 3x - 1</h2>
Step-by-step explanation:
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Below is the solution:
<span>distance = 475
</span>time = 9.5 hrs
<span>since distance and time varies directly
</span>
therefore in 9.5 hrs train travels 475 miles
=> In 1 hr train travels 475 / 9.5 miles = 50 miles
<span>and in 4 hrs train travells 50*4 i.e 200 miles </span>
The slopes of perpendicular lines are negative reciprocals.The slope of the given line is 4.The slope of the perpendicular is -1/4.
Now we need to find the equation of a line that has slope -1/4 and passes through the point (4, 20).
We use the point-slope form of the equation of a line, where m = slope, and the point is (x1, y1).
y - y1 = m(x - x1)
y - 20 = -1/4(x - 4)
-4y + 80 = x - 4
x + 4y = 84
Answer:
This cannot be answered without more information.
Step-by-step explanation:
