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3 years ago

In AABC, AC - BC. The length of AC is three times the length of AB. Find

Mathematics

1 answer:

Arlecino [84]3 years ago

5 0

Answer:

i don't undertsand this question

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Simplify. 1/4+x divided by 1/2

FinnZ [79.3K]

I think the answer is 1/4 + 2x :)

3 0

2 years ago

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The complex numbers corresponding to the endpoints of one diagonal of a square drawn on a complex plane are 1 + 2i and -2 – i.Wh

Musya8 [376]

On the complex plane, the number $a+bi$ is mapped onto the point with coordinates $(a,b)$ .

In other words, the x coordinate is the real part of the number, while the y coordinate is the complex part of the number.

Viceversa, if you start from a point $(x,y)$ , you can identify the number $x + iy$ .

So, the endpoints of the diagonal are the points $(1,2)$ and $(-2,-1)$ . These are points A and C in the attached figure.

This means that points B and D have coordinates

$B = (-2,2),\quad D = (1,-1)$

So, the correspondant complex numbers are

$B = (-2,2)\mapsto -2+2i,\quad D = (1,-1)\mapsto 1-i$

6 0

3 years ago

Sara is building a circular garden with a radius of 14 m. She can buy the fencing in

mojhsa [17]

Answer:

she need to buy 9 packs

Step-by-step explanation:

C = 2πr

= 2·3.14·14

= 87.92 m

she need to buy 9 packs

5 0

3 years ago

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How do you convert fraction to a decimal?

Romashka-Z-Leto [24]

$\huge\text{Hey there!}$

$\large\text{Some people usually convert fractions into decimals by DIVIDING}\\\large\text{the TOP number) by the DENOMINATOR (the BOTTOM number)}.$

$\large\text{Here is an EXAMPLE of what I meant!}$

$\large\text{Fraction: }\mathsf{\dfrac{5}{6}}$

$\large\text{Equation: } \mathsf{5\div6}$

$\large\text{Answer: } \mathsf{0.833333}$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

7 0

2 years ago

Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity

Anna11 [10]

Answer:

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is $\frac{LT^{-2}}{LT^{-1}}$

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0

3 years ago