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3 years ago

What is 75.4 in expanded form

Mathematics

1 answer:

Shalnov [3]3 years ago

8 0

Answer: 75.4 =

+ 5

+ 0.4

Step-by-step explanation:

Hope this helps :)

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Which inequality can be used to represent a number x that is less than equal to 8 and greater than -3

KIM [24]

Answer: x = -2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8

Solution:

A number line is used to represent the possible numbers that x can be.

x that is less than equal to 8 >>>> x ≤ 8

x is greater than -3 >>>> x > -3

So it will be represented as,

-3 < x ≤ 8

So all the numbers between -3 and 8 including eight (because it has the equal sign)

-2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8

7 0

3 years ago

3х + 9y - 8x - 2y +7

Sonja [21]

Answer:

-5x+7y+7

Step-by-step explanation:

3х + 9y - 8x - 2y +7 can be written like the equation below to help solve it

3x-8x+9y-2y+7

=-5x+7y+7

7 0

3 years ago

How to solve it because i have no idea

Angelina_Jolie [31]

First you chang top fractions into decimal add and divide that by 4 which is equal to 0.375 hope it helps.

5 0

2 years ago

If 63,000 = 6.3 x 10n, then what is n

tatyana61 [14]

Answer:

n is a neutron , the symbol n stands for neutron

4 0

2 years ago

Read 2 more answers

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

1 year ago