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german
3 years ago
14

What is 75.4 in expanded form

Mathematics
1 answer:
Shalnov [3]3 years ago
8 0

Answer: 75.4 =

 70  

+ 5  

+   0.4

Step-by-step explanation:

Hope this helps :)

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Which inequality can be used to represent a number x that is less than equal to 8 and greater than -3
KIM [24]

Answer:  x =  -2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8

Solution:

A number line is used to represent the possible numbers that x can be.

x that is less than equal to 8 >>>> x ≤ 8

x is greater than -3 >>>>  x > -3

So it will be represented as,

  -3 < x ≤ 8

So all the numbers between  -3 and 8 including eight (because it has the equal sign)

-2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8

7 0
3 years ago
3х + 9y - 8x - 2y +7​
Sonja [21]

Answer:

-5x+7y+7

Step-by-step explanation:

3х + 9y - 8x - 2y +7​ can be written like the equation below to help solve it

3x-8x+9y-2y+7

=-5x+7y+7

7 0
3 years ago
How to solve it because i have no idea
Angelina_Jolie [31]
First you chang top fractions into decimal add and divide that by 4 which is equal to 0.375 hope it helps.

5 0
2 years ago
If 63,000 = 6.3 x 10n, then what is n​
tatyana61 [14]

Answer:

n is a neutron , the symbol n stands for neutron

4 0
2 years ago
Read 2 more answers
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
1 year ago
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