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2 years ago

Expand (2−x)5 and identify each part of the expression. 80x2 -40 10 32

Mathematics

1 answer:

Finger [1]2 years ago

8 0

Answer:

<h3>coefficient to the 4th term, to the 5th term, etc.)</h3>

Step-by-step explanation:

i hope it helps :)

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What is the value of y in this equation?<br><br> 0.017y = 5.1

Ne4ueva [31]

I am guessing that y = 300.

Hope this helps

Happy Holidays.

8 0

2 years ago

Read 2 more answers

Please help if you can<br> 1. ( 6k+2) - (3k-2)

viktelen [127]

(6k+2)-(3k-2)
expand brackets 18k²-12k+6k-4
simplify 18k²-6k-4

4 0

3 years ago

Write 243 as a product of primes.

shtirl [24]

Answer:

243 = 3⁵

Step-by-step explanation:

Firstly we will find the factors of 243. On calculating it see that the factors of 243 are 3 x 3 x 3 x 3 x 3.

243 = 9 x 9 x 3

We need to write 243 as the product of primes.

The number that divides itself or 1 are prime numbers.

3 is the only prime number here such that,

243 = 3⁵

Hence, this is the required solution.

6 0

2 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

2 years ago

Go Math grade 6 standards practice workbook common core edition pages 101 & 102

notka56 [123]

Bruhhhhhhhhhhhbkfifjkgjdjcjcigcjc

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2 years ago