Start by finding the slope of the given equation by putting it into slope intercept form (which is y=mx+b). perpendicular lines have slopes that are opposite reciprocals of each other, so if the slope of one line is -1/2, the slope of the like perpendicular to it will be 2/1 (or just 2). your answer (in point slope form) should be: y-6 = -(3/4)(x-2), and you can adjust it if it needs to be in standard form (ax+by=c) or slope intercept form (y=mx+b).
(i) x = 3
(ii) y = 6
<u>Explanation:</u>
The two polygons are similar.
The congruent angles are:
∠J ≅ ∠G
∠R ≅ ∠M
∠I ≅ ∠A
∠C ≅ ∠T
∠E ≅ ∠H
Proportional sides are:
(i) Value of x = ?
Putting the values from the figure
(ii) Value of y = ?
On putting the value we get:
![\frac{6}{12} = \frac{x^2-4}{y+4} \\\\6(y+4) = 12(x^2 - 4)\\\\6y + 24 = 12[(3)^2 - 4]\\\\6y + 24 = 12[ 9 - 4]\\\\6y + 24 = 60\\\\6y = 36\\\\y = 6](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B12%7D%20%3D%20%5Cfrac%7Bx%5E2-4%7D%7By%2B4%7D%20%5C%5C%5C%5C6%28y%2B4%29%20%3D%2012%28x%5E2%20-%204%29%5C%5C%5C%5C6y%20%2B%2024%20%3D%2012%5B%283%29%5E2%20-%204%5D%5C%5C%5C%5C6y%20%2B%2024%20%3D%2012%5B%209%20-%204%5D%5C%5C%5C%5C6y%20%2B%2024%20%3D%2060%5C%5C%5C%5C6y%20%3D%2036%5C%5C%5C%5Cy%20%3D%206)
A. quadrant 2
b. quadrant 4
c. quadrant 3
I will right it sideways. you can use this strategy later on if you would like. I put (parentheses) around what is optional to include. the = to the left of the second word number is to show that the number is equal. if there are two different variables you would put a crossed out equal sign.
_______________
eight= 8 l
more than= +
six= 6
times= x
(a)number= n l
_______________
added (to)= +
_______________
one= 1 l
more than= +
= number= n l
_______________
(I tried to do parentheses)
then, you rewrite what you wrote beside the words!
(8+6n)+(1+n)
that is your equation!
