The given function is,

The graph can be drawn as,
The period will be distance between two consequetive maximas,

Thus, period is correct.
The amplitude can be determined as,

Thus, amplitue is incorrect.
The range is,

Thus, the range is correct.
The midline is,

Thus, the midline is correct.
Thus, option (b) is the solution.
Answer:
Enter a payment of 5192.52.
Step-by-step explanation:
Consider the provided information.
The payment is $4800 with a 4 month, 8% note.
The amount can be calculated as:

Where <em>p</em> is money invested, <em>r</em> is annual interest rate, <em>t</em> is number of years and <em>m</em> is number of period.
Now substitute p = 4800 r = 0.08 and m = 4 in the above formula.





Hence, enter a payment of 5192.52.
Isn't it 5?
I think it's 5 , I may be wrong idk.
Answer:
(x + 1)² = (2x)²
(1 + 1)² = (2(1))²
2² = 2²
4 = 4
(-1 + 1)² = (2(-13))²
(-12)² = (-26)²
Not true
x = -13 satisfies neither
If a function is defined as

where both
are continuous functions, then
is also continuous where defined, i.e. where 
So, in your case, this function is continous everywhere, except where

To solve this equation, we can use the formula 
It means that, if the leading terms is 1, then the x coefficient is the opposite of the sum of the roots, and the constant term is the product of the roots.
So, we're looking for two terms whose sum is 7, and whose product is 12. These numbers are easily found to be 3 and 4.
So, this function is continuous for every real number different than 3 or 4.