Is someone kind and available enough to do this work for me I need it really

Mathematics

1 answer:

Assoli18 [71]3 years ago

6 0

Answer:

D. 40.0km

Step-by-step explanation:

When rounding to 3 significant figures, we will have to look at the 4th significant figure. If that figure is 1-4, you round the 3rd figure down. If that figure is 5-9, you round the 3rd figure up.

In this case, the 3rd figure is the tenth 9 and the 4th figure is the hundredth 7.

Since 7 is from 5-9, you round the tenth 9 up. This adds one whole to 39, which makes it 40. You also need to keep 3 significant figures so the decimal zeros are significant. Thus, the answer is 40.0km

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Hector's service club is raising money by wrapping presents in the mall. The function f\left(x\right)=3xf(x)=3x describes the am

mestny [16]

Given:

The function f(x) describes the amount of money, in dollars, the club will earn for wrapping x presents.

$f(x)=3x$

To find:

The f(658).

Solution:

We have,

$f(x)=3x$

Substitute x=658 to find the value of f(658).

$f(658)=3(658)$

$f(658)=1974$

It means, the club will earn $1974 for wrapping 658 presents.

Therefore, $f(658)=1974$ .

7 0

3 years ago

between 1995 and 2006, the population of samburg, usa(in thousands) can be modeled by f(x) = 0.35x(squared) - 2.1x+15.8 where x=

Juli2301 [7.4K]

$\bf f(x)=0.35x^2-2.1x+15.8\qquad 
\begin{cases}
x=\textit{year since 1995}\\
f(x)=\textit{population amount}
\end{cases}$

the equation is a quadratic one, and it has a positive coefficient on the leading term, meaning, is opening upwards, so it has a "burrow" for the vertex.

the minimum or lowest point for a quadratic opening upwards is, well, the vertex point :), the "x" value is the year, the "y" or f(x) value is the population, we're asked for the year, or the x-coordinate of the vertex

well $\bf \begin{array}{llll}
f(x)=&0.35x^2&-2.1x&+15.8\\
&\quad \uparrow &\quad \uparrow&\uparrow \\
&\quad a&\quad b &c
\end{array}
\\\\

\\\\
\qquad \textit{vertex of a parabola}\\ \quad \\
\qquad 

\left(\boxed{-\cfrac{{{ b}}}{2{{ a}}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$