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3 years ago

(Best answer gets brainliest, Good answers get 5 stars, all answers get thanks.)

Mathematics

2 answers:

elena55 [62]3 years ago

5 0

Answer:

x=1

Step-by-step explanation:

To solve, we need to get x by itself. To do this, preform the opposite of what is being done to the equation, and everything that is done to one side, must be done to the other.

5(2x-8)+15= -15

First, subtract 15 from both sides, since 15 is being added

5(2x-8)+15-15=-15-15

5(2x-8)=-30

Next, divide both sides by 5 since 5 is being multiplied

5(2x-8)/5= -30/5

2x-8= -6

Add 8 to both sides, since 8 is being subtracted

2x-8+8= -6+8

2x= 2

Divide both sides by 2, since 2 is being multiplied

2x/2= 2/2

x=1

djyliett [7]3 years ago

4 0

Answer:

x=1

Step-by-step explanation:

5(2x-8)+15=-15

first do what is in parentheses, multiply the 5 with 2x and -8.

10x-40+15=-15

add 15 to -40

10x-25=-15

add 25 to both sides

10x=10

divide 10 on both sides

x=1

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3 years ago

There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t

beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways $=(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})$

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

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3 years ago

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scoray [572]

Answer:

The 95% confidence interval for those opposed is: (0.298, 0.334).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.