Answer:
......................................................
Step-by-step explanation:

should be the right answer
Answer: ( 77.27 , 83.93)
Therefore at 95% confidence/prediction interval is
= ( 77.27 , 83.93)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 80.6 words per minute
Standard deviation r = 7.2
Number of samples n = 18
Confidence interval = 95%
z(at 95% confidence) = 1.96
Substituting the values we have;
80.6+/-1.96(7.2/√18)
80.6+/-1.96(1.697056274847)
80.6 +/- 3.33
= ( 77.27 , 83.93)
Therefore at 95% confidence/prediction interval is
= ( 77.27 , 83.93)
2x^2 = 28 - x in standard form is 2x^2 + x = 28
Factoring, we have:
x(2x + 1) = 28
Well, here is how i would do it.
We start with 225, at a rate of 15% per year. Assuming your answers are in years and not months, we will increase by this increment; years.
So, we start with 225, and a 15%, or .15, increase. So what we would do, it take 225 times .15. One way ive learned to do this (via algebra class) is that you can times it by 1.15 to make it quicker, this just takes out the adding step.
So after one year, we would have a total of 258.75, or about 259 wolves.
after two years, we would have about 298 (we cant have a half of a wolf!)
after 3 years, we would have about 343 wolves.
after 4 years, we would have about 394 ish
after 5 years, we would have about 453
after 6 years, we would have about 521.
So, it would take about 5 and a half years, if thats an option choice.