144 I believe. You multiply length times width
Hi There!
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Slope Intercept Form: y = mx + b
Where: m = slope and b = y-intercept
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Question 11: The slope being 0.5 is the pay for the amount of miles he pays daily.
Question 12: y = 2x + 20
Question 13: y = 25x + 50
Question 14: y = 1/2x + 6
Question 15: y = 2x + 15
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Hope This Helps :)
Answer:
6750
Step-by-step explanation:
4 digit numbers are 1000,1001,1002,...,9999
let numbers=n
d=1001-1000=1
9999=1000+(n-1)1
9999-1000=n-1
8999+1=n
n=9000
now let us find the 4 digit numbers divisible by 4
4| 1000
______
| 250
4 |9999
_____
| 2499-3
9999-3=9996
so numbers are 1000,1004,1008,...,9996
a=1000
d=1004-1000=4
let N be number of terms
9996=1000+(N-1)4
9996-1000=(N-1)4
8996=(N-1)4
N-1=8996/4=2249
N=2249+1=2250
so number of 4 digit numbers not divisible by 4=9000-2250=6750
Answer:
b = 4.66666667
Step-by-step explanation:
The equation for finding the area of a triangle is
0.5b x h = a
b = base
h = height
a = area
So I calculated 14 divided by 6
And got 2.3333333
And since that number is half of the base, I multiplied it by 2
2.333 x 2 ≈ 4.66666667
Answer: t-half = ln(2) / λ ≈ 0.693 / λExplanation:The question is incomplete, so I did some research and found the complete question in internet.
The complete question is:
Suppose a radioactive sample initially contains
N0unstable nuclei. These nuclei will decay into stable
nuclei, and as they do, the number of unstable nuclei that remain,
N(t), will decrease with time. Although there is
no way for us to predict exactly when any one nucleus will decay,
we can write down an expression for the total number of unstable
nuclei that remain after a time t:
N(t)=No e−λt,
where λ is known as the decay constant. Note
that at t=0, N(t)=No, the
original number of unstable nuclei. N(t)
decreases exponentially with time, and as t approaches
infinity, the number of unstable nuclei that remain approaches
zero.
Part (A) Since at t=0,
N(t)=No, and at t=∞,
N(t)=0, there must be some time between zero and
infinity at which exactly half of the original number of nuclei
remain. Find an expression for this time, t half.
Express your answer in terms of N0 and/or
λ.
Answer:
1) Equation given:
← I used α instead of λ just for editing facility..
Where No is the initial number of nuclei.
2) Half of the initial number of nuclei:
N (t-half) = No / 2So, replace in the given equation:
3) Solving for α (remember α is λ)
αt ≈ 0.693
⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ