The wheel has diameter 60 cm = 0.60 m, and thus circumference π(0.60 m) ≈ 5.923 m.
In one complete revolution, a point on the edge of the wheel covers this distance, so that the wheel has an angular speed of
(13.2 m/s) * (1/5.923 rev/m) ≈ 2.229 rev/s
There are 60 seconds to each minute, and 60 minutes to each hour, so converting to rev/h gives
(2.229 rev/s) * (60 s/min) * (60 min/h) ≈ 8024 rev/h
8/5
I divided from both sides and flip the equation
G=38
Whenever you divide or multiply by one the number stays the same, therefore just take out all the xs and then solve the equation. I hope this helps!
At first let us choose the 5 points
at x = 0, y = 0
The first point is (0, 0)
![y=ax^3](https://tex.z-dn.net/?f=y%3Dax%5E3)
We will choose a = 1/2
The points are
(-2, -4)
(-1, -1/2)
(0, 0)
(1, 1/2)
(2, 4)
(9x+1)=(7x+13)
2x+1=13
2x=12
x=6
7(6)+13
42+13
55
180-55
125
y= 125°