In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
Answer:
2.547 = x
Step-by-step explanation:
tan 23 = x/6 Use this equation to find the value of x
0.4245 = x/6 Multiply both sides by 6
2.547 = x
Answer:
16/25
Step-by-step explanation:
64% =
64/100 =
16/25
Answer:
x is 10
Step-by-step explanation:
Form the diagram, you can see that UV is parallel to TS, this means that <UVS = < UTS
Given
<UVS = 5x + 38
<UTS = 12x - 28
Since the sum of opposite angle of a quadrilateral is 180 degrees, hence;
5x + 38 + 12x - 28 = 180
Collect like terms
5x + 12x - 28 + 38 = 180
17x + 10 = 180
17x = 180-1-
17x = 170
x = 170/17
x = 10
hence the value of x is 10
