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Vladimir79 [104]
3 years ago
11

What is the nearest whole percent of 45

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0

Answer:

Step-by-step explanation: 45% based on the way you state the question. 45% is a whole percent.

Rainbow [258]3 years ago
5 0
45 percent is the nearest whole percent
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HELP PLEASE
Stella [2.4K]

Answer:

The right answer is: 14,256 cubic inches

Step-by-step explanation:

First of all, let's identify the dimensions of the tank and convert them to inches

Knowing that  1 Feet = 12 inches

So, the dimensions of the tank, expresed in inches will be:

Height (H): 2 ft. x 12 = 24 inches

Width (W): 1.50 ft. x 12 = 18 inches

Lenght (L): 3 ft. x 12 = 36 inches

Before calculating the volume of water inside the thank, We must consider that <em>there are two inches of empty space at the top.</em>

So , We must substract 2 inches to the height to calculate the volume.

Then, the height used for calculating the volume will be:

H'= 24 inches - 2 inches = 22 inches

Then,

Volume (V)= W x L x H'

V= (18 inches) x (36 inches) x (22 inches)

V= 14,256 cubic inches

8 0
3 years ago
Which statement is true about this equation? -9(x-3)+12=-3(2x+5)-3x
Finger [1]

Answer:

Any value of "x" makes the equation true

Step-by-step explanation:

(-∞,∞)

All real numbers

i hope this work for you

8 0
2 years ago
HELP ME PLZ URGENT DUE TODAY
storchak [24]

Answer:

8377

Step-by-step explanation:

Growth rate is exponential, so it is determined by the formula (1+growth rate)^n where n is years

1.035^15 = 1.675...

multiply by 5000, you get 8376.744....

7 0
3 years ago
Find the sum of odd numbers which are divisible by 3 and lie between 1 and 500
Zolol [24]

Answer:

20,667.

Step-by-step explanation:

This is an arithmetic series:

3 + 9 + 15 + 21 + 27+ ...........+ 495

First term = 3 and common difference = 6.

Number of terms = ( 495 - 3 )/6 + 1

= 83.

So Sn = n/2(a1 + l)      where a1 = first term and l = last term

S83 = 83/2(3 + 495)

= 41.5 * 498

= 20,667.

7 0
2 years ago
NEED HELP !!!!!! READDD THE QUESTION THERE ARE TWO PARTS
mel-nik [20]

We have to find horizontal component of Mayosons velocity.

#a

\\ \tt\bull\leadsto V_x=vsin\theta

\\ \tt\bull\leadsto V_x=2.5sin36

\\ \tt\bull\leadsto V_x=2.5(0.58)

\\ \tt\bull\leadsto V_x=1.45m/s

#b

Here 2 vectors A=8 and B=2.5

\\ \tt\bull\leadsto \overrightarrow{R}

\\ \tt\bull\leadsto \sqrt{A^2+B^2+2ABcos\Theta}

\\ \tt\bull\leadsto \sqrt{8^2+2.5^2+2(8)(2.5)cos36}

\\ \tt\bull\leadsto \sqrt{64+6.25+40(0.8)}

\\ \tt\bull\leadsto \sqrt{70.25+32}

\\ \tt\bull\leadsto \sqrt{102.25}

\\ \tt\bull\leadsto 10.15m/s

3 0
2 years ago
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