Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are

. We can write these sequentially as

where

.
So the integral is approximately

Recall that



so our sum becomes

Do 45/225 and simplify and that’s your answer
Answer:
Step-by-step explanation:
Good Morning If you can be more specific i can help you with this question but there is no table text me back if oyu still need help! ;)
Answer:
3.58
Step-by-step explanation:
You have to divide 304 by 85
you will get 3.57647058824
You have to round it to the nearest hundedth which will leave you with 3.57