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3 years ago

Select the set of measurements that can form a triangle.

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

Step-by-step explanation:

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Evaluate the expression: −(8 − 12) + 60 + (−4)2.<br> A) 13<br> B) 20<br> C) 21<br> D) −11

k0ka [10]

Answer:

56.

Step-by-step explanation:

= -(8-12)+60+(-4)*2

= -(-4)+60+(-4)*2

= 4+60+(-4)*2

= 4+60+-4*2

= 4+60-4*2

= 4+60-8

= 64-8

= 56

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3 years ago

100 POINTS

gulaghasi [49]

C. Alternate interior angles are formed by a transverse line intersecting two parallel lines . They are located between the two parallel lines but on opposite sides of the transverse line

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2 years ago

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3. Put the following numbers in order

PtichkaEL [24]

Answer:

3.85 x 10-7

8.53 x 10-5

0.00000538

3.58 x 10-6

Step-by-step explanation:

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3 years ago

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Which fraction is the greatest (represents the largest quantity) 1/3 3/8 2/5 1/2?

ale4655 [162]

1/2 is the largest fraction out of all of them

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3 years ago

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

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3 years ago