Answer:
x = 1
Step-by-step explanation:
To solve for a variable, you need to get the variable on one side of the equation, and by itself.
4x + 5 = x + 8
4x = x + 3 --- subtract 5 from both sides
3x = 3 --- subtract x from both sides
x = 1 --- divide both sides by 3
Step-by-step explanation:
Because the length of ST is calculated using pythagorean theorem:

Where the square of the hypotenuse is equal to the sum of squares of the other two sides of a right triangle. In this case, the hypotenuse is ST and the other two sides are distances between S and T over the X and Y axis. Those are easily calculated:

Where x is the distance between S and T over X axis and Y distance over Y axis, sx and tx are X coordinates of S and T, sy and ty are Y coordinates of S and T.
Using that formula, you get that y = 17 and x = 8.
Back to the pythagorean theorem, if we put those number in the formula of the pythagorean theorem, we get something like this:

And finally, the correct answer is in fact 353.
Answer:
Let's see what to do buddy...
Step-by-step explanation:
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


Subtract the sides of the equation plus<em> </em><em>1</em><em>1</em> :


Subtract the sides of the equation plus <em>1</em><em>0</em><em>x</em>


Divided the sides of the equation by <em>9</em><em> </em>


And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer attached, but more letters needed
Regression 1. Urstsitdyxkyxktakgzkydlyxkyskgz