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Mashutka [201]
3 years ago
14

A cone with a height of 8 inches and a radius of 6 inches was dilated using a scale factor of 2. Which

Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

true yes sir

Step-by-step explanation:

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Help due tonight<br> plssss
postnew [5]

Answer:

Perpendicular to base

Step-by-step explanation:

The cut creates two rectangular prisms (each angle must be 90 degrees)

The cut is perpendicular to the base

6 0
3 years ago
Edward is playing a game where he draws cards with integers on them from a deck of cards. If the integer is positive he moves fo
Murljashka [212]
B) 4 steps in front of where he started.
4 0
4 years ago
Help me plot please.
Veronika [31]
One at 100,18 one at 200,14 one at 150,15 one at 125,20 and one at 225,12
4 0
3 years ago
Read 2 more answers
Julia has 2 identical rooms in her house. If each room measures 8 feet on one side and 12 feet on another, what is the total are
levacccp [35]
L = 12 ft
W = 8 ft
One room has area:
A1 = L · W = 12 · 8 = 96 ft²
The total area of rooms:
A = 2 · 96 = 192 ft² 
6 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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