If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
The lengths of AC and AB are each 10.6 units.
<u>Step-by-step explanation</u>:
Perimeter of a triangle = Sum of all the three sides of a triangle
- Perimeter = 3a
- where, a is the length of the each sides of a triangle.
⇒ 32 = 3a
⇒ a = 32/3
⇒ a = 10.6
