In a bar graph space between rectangles is always

Mathematics

1 answer:

bezimeni [28]2 years ago

7 0

Answer:

the same

Step-by-step explanation:

Not as histograms where space must equal 0 as calculating area is needed.

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Use the Law of Sines to solve the following triangle. Approximate your answers to the nearest tenths. c = 10.2 in, A = 45.1° B =

Sergeu [11.5K]

Law of sines says
a/sinA=b/sinB=c/SinC
where a,b,c are sides of a triangle and A,B,C are angles respectively.
a/sin45.1=c/sin59.1

(we can find angle C by sum of angles of a triangle is 180.)

a=sin(45.1) x 10.2/sin (59.1)

a=0.708 x 10.2/0.85
a=8.496
a=8.5 units

now u can find b and c sides.

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2 years ago

The volume of a pyramid that fits exactly inside a cube is 10 cubic feet. What is the volume of the cube?

Tatiana [17]

Answer:

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3 years ago

the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the

Elanso [62]

1st number = x

2nd number = 3x

3rd number = 2x-10

x +3x + 2x-10 =92

6x - 10 = 92

6x =102

x = 102/6

x = 17

1st number = 17

2nd number = 17*3 = 51

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What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$