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4 years ago

The other one is for the two variable equation y = 3x + 4 find the matching y value when x = 0

1 answer:

5 0

In finding the matching value of one unknown variable when other is known we have to use substitution. By way of substitution, y = 3 (0) + 4; y = 4. Moreover, when the variable of the known variable is zero, we just have to identify the intercept of line in the equation. The number with no variable in its side is always the intercept of the equation.

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-5: -2; 1;<br><br>write the next 3 terms

Nataly_w [17]

Answer:

Next 3 of the sequence are 4, 7, 10

You are adding by 3.

-2 - -5= 3

-2 + 3=1

1+3=4

4+3=7

7+3=10

5 0

3 years ago

Anybody know the answers to this frl it’s due in 15 mins

hammer [34]

Answer:

4. j(11) = 8

I think it is linear

5. g(-3) = 18

No, it's a parabola since x is to the second power

6. f(-7) = 5

No, I think it's an absolute value function

7. h(0) = 13

I think it is linear, just the slope is 0

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Pleas3 HALLLLP ME EEE

Sveta_85 [38]

Answer:

Step-by-step explanation:

For example, x=1, y=2

Y=x+2

Y=1+2

Y=3

6 0

3 years ago

Read 2 more answers

Is 0.313311333111......... a repeating decimal?

abruzzese [7]

No, a Repeating Decimal could be .777 ... Or it could also be something Like .657657657

The decimal you presented is not a form of a repeating decimal.

4 0

3 years ago

Read 2 more answers

List all possible rational zeros given by the Rational Zeros Theorem (but don't check to see which actually are zeros). (Enter y

spin [16.1K]

Answer:

$\pm 1,\pm 2, \pm 3, \pm 4, \pm 6, \pm 12, \pm \dfrac{1}{2},\pm \dfrac{3}{2},\pm \dfrac{1}{3},\pm \dfrac{2}{3},\pm \dfrac{4}{3},\pm \dfrac{1}{6}.$

Step-by-step explanation:

According to the rational root theorem, the all possible rational roots of a polynomial are in the form of $\pm \dfrac{p}{q}$ , where p is a factor of constant and q is a factor of leading coefficient.

The given polynomial is

$S(x)=6x^4-x^2+3x+12$

Here, leading term is 6 and constant is 12.

Factors of 6 are ±1, ±2, ±3 and ±6.

Factors of 12 are ±1, ±2, ±3, ±4, ±6 and ±12.

Using rational root theorem, the all possible rational roots of given polynomial is

$\pm 1,\pm 2, \pm 3, \pm 4, \pm 6, \pm 12, \pm \dfrac{1}{2},\pm \dfrac{3}{2},\pm \dfrac{1}{3},\pm \dfrac{2}{3},\pm \dfrac{4}{3},\pm \dfrac{1}{6}.$

3 0

3 years ago