Please help me with these two problems!!! There due in a hour

4x + 12 = -7y -y + 12 = 4x Solve with elimination

statuscvo [17]

Take the second equation and flip it around so the y on the left ends up on the right and the 4x on the right ends up on the left. This makes all negatives positive and all positives negative. -4x + 12 = y

Then add the first equation to the second equation
4x +12 = -7y
-4x + 12 = y this eliminates the x's
24 = - 6y then divide by - 6
- 6 - 6
- 4 = y

So if you know that y = negative 4, you can substitute into either equation. I pick the second one because I am a lazy person.
-y + 12 = 4 x
-(-4) + 12 = 4 x combine your numbers
 16 = 4 x then divide by 4
 4 = x
So your solution is: x = 4 and y = -4 or this is also written (4, -4)

Does that work for you?

4 0

3 years ago

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After multiplying, a calculator screen displays the answer shown below. How would you write this number in standard form? Enter

Aliun [14]

Answer:

$8.234 E14=8.234 \times 10^{14}$

Step-by-step explanation:

The given number is $8.234 E14$

We need to write this number in standard form.

Any no is given in the standard form is given by :

$N=a\times 10^b$

Where

a and b is real no and integer

It means,

$8.234 E14=8.234 \times 10^{14}$

Hence, this is the required solution.

6 0

3 years ago

It takes Maya 30 minutes to solve 5 logic puzzles and it takes Amy 28 minutes to solve 4 logic puzzles use models to show the ra

Contact [7]

Answer:

MAYA (6 minutes)

Amy (7 minutes)

Step-by-step explanation:

MAYA

Takes Maya 30 minutes to solve 5 Puzzle:

Let's express it as,

30 mins = 5 Puzzle

1 min = x Puzzle

Cross multiply to solve for the number of questions Maya solves in a minute.

It becomes:

30*x = 5*1

30x = 5

x = 30/5

x = 6mins.

It means it takes Maya 6 mins to solve one question.

FOR AMY

Takes Amy 28 mins to solve 4 puzzles.

Let's represent it as:

28 mins = 4 Puzzles

x min = 1 puzzle

Let's solve for x

(28 mins) * (1 puzzle) = 4 * x

28 = 4x

x = 28/4

x = 7 mins

It means, it takes Amy 7 minutes to solve 1 puzzle

3 0

3 years ago

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Five distinct numbers are randomly distributed to players numbers 1 through 5. Whenever two playerscompare their numbers, the on

ad-work [718]

Answer:

Observe that the first and the second player have equal probability to get any of number. Using the principle of that symmetry, we have that

$P(X=0)=\frac{1}{2}$

Event X = 1 means that the first player has got greater number than the second player, but not than the third player. So, choose any three numbers out of five of them and say that the minimal number out of these three goes to the second player, mean number to the first one and the largest to the third one. Permute remaining two numbers on remaining two people. Hence

$P(X=1)=\frac{1}{6}$

Event X = 2 means that the first player has got greater number than the second and the third player, but not than the fourth player. So, choose any four numbers out of five of them and say that the minimal number and the next minimal out of these four go to the second and the third player (and permute them), third number to the first one and the largest to the fourth player. Give remaining number to the last person. Hence

$P(X=2)=\frac{1}{12}$

Event X = 3 means that the first player has got greater number than the second, the third, and the forth player, but not than the fifth player. So, permute these five numbers as follows: give the highest to the last person, the second highest to the first, and permute remaining numbers on the remaining people. Hence

$P(X=3)=\frac{1}{20}$