Answer:
Therefore the triangles are congruent by Angle Angle similarity postulate.
ΔEFG ~ ΔHJK ...{ By Angle-Angle similarity postulate}
Step-by-step explanation:
Given:
In right triangle ΔEFG
m∠E= 25°.
In right triangle ΔHJK,
m∠H=25º
To Prove:
ΔEFG ~ ΔHJK
Proof:
In right triangle ΔEFG and ΔHJK
m∠ E ≅ m∠ H .......{measure of each angle is 25° given}
m∠ F ≅ m∠ J .........{Both triangle is Right angle Triangle therefore measure angle is 90° each}
∴ ΔEFG ~ ΔHJK ...{ By Angle-Angle similarity postulate}
Therefore the triangles are congruent by Angle Angle similarity postulate.
ΔEFG ~ ΔHJK ...{ By Angle-Angle similarity postulate}
Answer:
-3y = -4x + 6
3y = 4x - 6
y = (4/3)x - 2
y + 5 = (4/3)(x - 3)
y + 5 = (4/3)x - 4
y = (4/3)x - 9
Step-by-step explanation:
The answer is: [D]: " y = x² + 2x + 2 " .
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Answer:
32/63
Step-by-step explanation:
i used a calculator
Answer:b
Step-by-step explanation: