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3 years ago

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Answer to: (a - 3b)(2a - 5b) distributive form

1 answer:

Alina [70]3 years ago

5 0

When I look at a problem like this, I think of the FOIL method. This method states "You multiply integers in the order of First, Outside, Inside, Last, and then add them together"

(a -3b)(2a - 5b)

First --- 2a * a
Out --- (-5b) * a
In --- (-3b) * 2a
Last --- (-3b) * (-5b)

2a² - 5ab -6ab + 15b²

2a² - ab + 15b²

This would be your answer in simplest form!

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2 years ago

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3 years ago

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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3 years ago

2x + 8 = 3x + x + 18<br> how do i solve this

Gnoma [55]

Answer:

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Step-by-step explanation:

reorder the terms: 8+2x=18+3x

solve: 8+2x=18+3x

-3x -3x

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8-1x=18

-8. -8

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-1x= 10

__ __

-1 -1

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<u>x= -10</u>

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3 years ago