Answer: 9.82cm
Step-by-step explanation:
5.75/100 * 6000
0.0575 * 6000=
345
Answer:
\bold{\text{Slope (m)}=\dfrac{1}{4}}Slope (m)=41
Step-by-step explanation:
A linear equation is of the form: y = mx + b where
m is the slope
b is the y-intercept (where it crosses the y-axis)
x + 4y = 16
4y = -x + 16
y = -\dfrac{1}{4}x+\dfrac{16}{4}y=−41x+416
y=-\dfrac{1}{4}x+4y=−41x+4
The y-intercept (b) = 4
Next, find the slope given point (4, 5) and b = 4
\begin{gathered}y=mx+b\\\\5=m(4)+4\\\\1=4m\\\\\dfrac{1}{4}=m\\\\\\\\\large\boxed{Slope (m)=\dfrac{1}{4}}\end{gathered}y=mx+b5=m(4)+41=4m41=mSlope(m)=41
Answer:
x = 1/2
, y = 3/2
Step-by-step explanation:
Solve the following system:
{3 y + x = 5
-2 x - 4 = -5
Hint: | Choose an equation and a variable to solve for.
In the second equation, look to solve for x:
{3 y + x = 5
-2 x - 4 = -5
Hint: | Isolate terms with x to the left hand side.
Add 4 to both sides:
{3 y + x = 5
-2 x = -1
Hint: | Solve for x.
Divide both sides by -2:
{3 y + x = 5
x = 1/2
Hint: | Perform a substitution.
Substitute x = 1/2 into the first equation:
{3 y + 1/2 = 5
x = 1/2
Hint: | Choose an equation and a variable to solve for.
In the first equation, look to solve for y:
{3 y + 1/2 = 5
x = 1/2
Hint: | Isolate terms with y to the left hand side.
Subtract 1/2 from both sides:
{3 y = 9/2
x = 1/2
Hint: | Solve for y.
Divide both sides by 3:
{y = 3/2
x = 1/2
Hint: | Sort results.
Collect results in alphabetical order:
Answer:{x = 1/2
, y = 3/2
Answer:
Equation of circle in standard form with centre (0, – 10) and radius 6. ![\mathbf{x^2+(y+10)^2=36}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%5E2%2B%28y%2B10%29%5E2%3D36%7D)
Step-by-step explanation:
We need to write equation of circle in standard form with centre (0, – 10) and radius 6.
The equation of circle is: ![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
where (h,k) is centre of circle and r is radius
We are given centre (0,-10) so, h=0, k=-10 and radius r = 6
Putting values and finding equation:
![(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2%5C%5C%28x-0%29%5E2%2B%28y-%28-10%29%29%5E2%3D%286%29%5E2%5C%5Cx%5E2%2B%28y%2B10%29%5E2%3D36)
So, equation of circle in standard form with centre (0, – 10) and radius 6. ![\mathbf{x^2+(y+10)^2=36}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%5E2%2B%28y%2B10%29%5E2%3D36%7D)