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Verdich [7]
3 years ago
9

Answer the question provided in the picture below.

Mathematics
2 answers:
FromTheMoon [43]3 years ago
6 0

Answer:

Finding area: multiply length by width (multiply the top length by the side length)

Finding perimeter: Add the lengths of all of the sides together

Step-by-step explanation:

klio [65]3 years ago
4 0

Answer: see the explanation

Step-by-step explanation:The perimeter is the distance around the outside of a shape. Perimeter is measured in units (e.g., cm). The area is the amount of space the inside of the shape takes up. Area is measured in square units (e.g., cm2).

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Step-by-step explanation:

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8 0
3 years ago
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Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
kotykmax [81]

Answer:

f'(x) = -\frac{2x}{1 - x^{2}}

Step-by-step explanation:

The derivative of an addition/subtraction of terms is the addition/subtraction of the derivatives of these terms.

The derivative of a constant is 0.

The derivative of a*x^{n} is a*n*x^{n-1}. The derivative of x^{3} is 3x^{2}, for example.

The derivative of the ln function:

If we have:

y = \ln{g(x)}

The derivative is

y' = g'(x)*\frac{1}{g(x)}

In this problem, we have that:

y = \ln{1 - x^{2}}

So g(x) = 1 - x^{2} and g'(x) = -2x

So the derivative to this function is

f'(x) = -\frac{2x}{1 - x^{2}}

8 0
3 years ago
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3 years ago
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Answer:

Step-by-step explanation:

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5 0
3 years ago
Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)
alekssr [168]

We are given coordinates of a continuous function f(x)

(–2, 0)

(0, –2)

(2, –1)

(4, 0).

We need to find the possible turning point for the continuous function.

<u>Note: Turning point is a point on the graph where slope of the curve changes from negative to positive or positive to negative.</u>

<em>A turning point is always lowest or highest point of the curve (where bump of the graph seen).</em>

For the given coordinates we can see that  (–2, 0) and (4, 0) coordinates are in a same line, that is on the x-axis.

But the coordinate  (0, –2) is the lowest point on the graph.

Therefore, (0, –2) is the turning point for the continuous function given.


3 0
3 years ago
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