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givi [52]
3 years ago
13

Almost 7 over 16 of the total water supplied to a household is wasted because of leaky faucets. Determine the decimal equivalent

of 7 over 16.
Use words to explain if the decimal terminates or repeats.
Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

0.4375

Step-by-step explanation:

7/16 is equal to 0.4375

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Meghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount of th
kupik [55]

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67 eghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount

Step-by-step explanation:

4 0
3 years ago
Part A: Abe rented a bike at $36 for 5 days. If he rents the same bike for 8 days, he has to pay a total rent of $48. Write an e
worty [1.4K]

a)

y=4 x +(1.6 X 10)


b)

y=4x +16


c)

x=0 y=0+16 (0,16)

x=1 y=4 +16 (1,20) first day it cost $20

x=2 y=8+16 (2,24) second day it cost $24

x=3 y=12+16 (3, 28) third day it cost $28


plot (0,16) , (1,20), (2,24), (3, 28)


i hope this help

7 0
3 years ago
HELP ME ASAPP<br><br><br> I have to turn it it in 7 minutes so plssss help me!!
lora16 [44]

Answer:

1/6

Step-by-step explanation:

Its a 1/6 chance it lands on the one u want

8 0
2 years ago
Read 2 more answers
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Ln x=-3<br> How to solve
Natasha2012 [34]

Answer: x=0.050

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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