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SVETLANKA909090 [29]
3 years ago
8

The ratio of dogs to cats at the local pet store is 5 to 8. If there are 96 cats, how many dogs are there?​

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

dogs 5:8 cats

96/8 = 12

12 X 5 = 60

there are 60 dogs

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To solve this question, we need to understand the normal probability distribution and the central limit theorem.

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Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

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Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

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