All categories

2 years ago

PLEASE HELP 20 POINTS!! QUESTION IS AN IMAGE

Mathematics

1 answer:

prisoha [69]2 years ago

5 0

Okay, so first off, if you need to graph anything, I suggest Desmos, it's a website with an online graphing calculator. It saved my life for highschool geometry.

Now, to answer your question, your y-intercept is going to be at point (0,2). Your x-intercepts are going to be at points (-2,0) and (-4,0). Your point is at (-3,-1). And then your lines simply extend from there.

Hope this isn't too late to be helpful, good luck with your assignments.

You might be interested in

AP CAL AB HELP!

Paul [167]

Answer:

$\frac{dc}{dt}\approx13.8146\text{ km/min}$

Step-by-step explanation:

We know that the plane travels at a <em>constant</em> speed of 14 km/min.

It passes over a radar station at a altitude of 11 km and climbs at an angle of 25°.

We want to find the rate at which the distance from the plane to the radar station is increasing 4 minutes later. In other words, if you will please refer to the figure, we want to find dc/dt.

First, let's find c, the distance. We can use the law of cosines:

$c^2=a^2+b^2-2ab\cos(C)$

We know that the plane travels at a constant rate of 14 km/min. So, after 4 minutes, the plane would've traveled 14(4) or 56 km So, a is 56, b is a constant 11. C is 90+20 or 115°. Substitute:

$c^2=(56)^2+(11)^2-2(56)(11)\cos(115)$

Evaluate:

$c^2=3257-1232\cos(115)$

Take the square root of both sides:

$c=\sqrt{3257-1232\cos(115)}$

Now, let's return to our law of cosines. We have:

$c^2=a^2+b^2-2ab\cos(C)$

We want to find dc/dt. So, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2+b^2-2ab\cos(C)]$

Since our b is constant at 11 km, we can substitute this in:

$\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-(11)^2-2a(11)\cos(C)]$

Evaluate:

$\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-121-22a\cos(C)]$

Implicitly differentiate:

$2c\frac{dc}{dt}=2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}$

Divide both sides by 2c:

$\frac{dc}{dt}=\frac{2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}}{2c}$

Solve for dc/dt. We already know that da/dt is 14 km/min. a is 56. We also know c. Substitute in these values:

$\frac{dc}{dt}=\frac{2(56)(14)-22\cos(115)(14)}{2\sqrt{3257-1232\cos(115)}}$

Simplify:

$\frac{dc}{dt}=\frac{1568-308\cos(115)}{2\sqrt{3257-1232\cos(115)}}$

Use a calculator. So:

$\frac{dc}{dt}\approx13.8146\text{ km/min}$

And we're done!

6 0

3 years ago

Noreen can walk a mile in 12 minutes. What is her average speed in miles per hour?

coldgirl [10]

Answer:

1.67 m/s is her average speed per hour.

Step-by-step explanation:

4 0

2 years ago

In basketball, some baskets are worth two points. Others are worth three points. In one game, the ratio of three-point basket

Alex787 [66]

The number of three-point tries is 36.

<h3>What are ratios?</h3>

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

<h3 /><h3>What is the number of three point tries?</h3>

The first step is to determine the total number of tries and baskets: (27 X 7)/3 = 63

Number of three-point tries = (4/7) x 63 = 36

To learn more about ratios, please check: brainly.com/question/25927869

4 0

2 years ago

-10 < -15 true or false ? Explain if true or false

Charra [1.4K]

Answer:

true

Step-by-step explanation:

3 0